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Additional Mathematics

Additional Mathematics Formula Book

PDF
Matthew Williams
|May 17, 2026|9 min read
Paper 01Paper 02ReferenceSection 1Section 2Section 3Section 4

All key formulas, identities, rules, and results organised by syllabus section and topic for CSEC Additional Mathematics.

Section 1: Algebra, Sequences and Series

A. Algebra

Remainder Theorem: When f(x)f(x)f(x) is divided by (x−a)(x - a)(x−a), the remainder is f(a)f(a)f(a).

Factor Theorem: (x−a)(x - a)(x−a) is a factor of f(x)f(x)f(x) if and only if f(a)=0f(a) = 0f(a)=0.

B. Quadratics

For ax2+bx+c=0ax^2 + bx + c = 0ax2+bx+c=0:

x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}x=2a−b±b2−4ac​​

Vertex form a(x+h)2+ka(x + h)^2 + ka(x+h)2+k, vertex at (−h, k)(-h,\, k)(−h,k):

h=b2ak=c−ah2h = \frac{b}{2a} \qquad k = c - ah^2h=2ab​k=c−ah2

Discriminant Δ=b2−4ac\Delta = b^2 - 4acΔ=b2−4ac:

Δ\DeltaΔNature of roots
Δ>0\Delta > 0Δ>0Two distinct real roots
Δ=0\Delta = 0Δ=0One repeated real root
Δ<0\Delta < 0Δ<0No real roots

Vieta's formulas for roots α\alphaα and β\betaβ of ax2+bx+c=0ax^2 + bx + c = 0ax2+bx+c=0:

α+β=−baαβ=ca\alpha + \beta = -\frac{b}{a} \qquad \alpha\beta = \frac{c}{a}α+β=−ab​αβ=ac​

ExpressionHow to evaluate
α2+β2\alpha^2 + \beta^2α2+β2(α+β)2−2αβ(\alpha + \beta)^2 - 2\alpha\beta(α+β)2−2αβ
(α−β)2(\alpha - \beta)^2(α−β)2(α+β)2−4αβ(\alpha + \beta)^2 - 4\alpha\beta(α+β)2−4αβ
1α+1β\dfrac{1}{\alpha} + \dfrac{1}{\beta}α1​+β1​α+βαβ\dfrac{\alpha + \beta}{\alpha\beta}αβα+β​
α2β+αβ2\alpha^2\beta + \alpha\beta^2α2β+αβ2αβ(α+β)\alpha\beta(\alpha + \beta)αβ(α+β)

Forming a new quadratic from known sum SSS and product PPP:

x2−Sx+P=0x^2 - Sx + P = 0x2−Sx+P=0

Multiply through by a constant if needed so that a,b,c∈Za, b, c \in \mathbb{Z}a,b,c∈Z.

C. Inequalities

Quadratic inequalities: find the critical values (roots), sketch the parabola, read the solution set from the graph.

Rational inequalities f(x)g(x)≶k\dfrac{f(x)}{g(x)} \lessgtr kg(x)f(x)​≶k: rearrange to get zero on one side, find critical values (roots and excluded values), apply a sign diagram.

D. Surds, Indices, and Logarithms

Surd rules:

a×b=abab=aba×a=a\sqrt{a} \times \sqrt{b} = \sqrt{ab} \qquad \frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}} \qquad \sqrt{a} \times \sqrt{a} = aa​×b​=ab​b​a​​=ba​​a​×a​=a

Rationalise using the conjugate: (a+b)(a−b)=a−b(\sqrt{a} + \sqrt{b})(\sqrt{a} - \sqrt{b}) = a - b(a​+b​)(a​−b​)=a−b.

Laws of indices:

LawRule
am×ana^m \times a^nam×anam+na^{m+n}am+n
am÷ana^m \div a^nam÷anam−na^{m-n}am−n
(am)n(a^m)^n(am)namna^{mn}amn
a0a^0a0111
a−na^{-n}a−n1an\dfrac{1}{a^n}an1​
am/na^{m/n}am/namn\sqrt[n]{a^m}nam​
(ab)m(ab)^m(ab)mambma^m b^mambm

If am=ana^m = a^nam=an and a≠0, 1a \neq 0,\, 1a=0,1, then m=nm = nm=n.

Logarithm definition: ax=b  ⟺  log⁡ab=x(a>0,  a≠1,  b>0)a^x = b \iff \log_a b = x \quad (a > 0,\; a \neq 1,\; b > 0)ax=b⟺loga​b=x(a>0,a=1,b>0)

Key values: log⁡a1=0\log_a 1 = 0loga​1=0, log⁡aa=1\log_a a = 1loga​a=1.

Laws of logarithms:

LawStatement
Productlog⁡a(xy)=log⁡ax+log⁡ay\log_a(xy) = \log_a x + \log_a yloga​(xy)=loga​x+loga​y
Quotientlog⁡a ⁣(xy)=log⁡ax−log⁡ay\log_a\!\left(\dfrac{x}{y}\right) = \log_a x - \log_a yloga​(yx​)=loga​x−loga​y
Powerlog⁡a(xn)=nlog⁡ax\log_a(x^n) = n\log_a xloga​(xn)=nloga​x

To solve ax=ba^x = bax=b: apply log⁡\loglog to both sides and use the power law: x=log⁡blog⁡ax = \dfrac{\log b}{\log a}x=logalogb​.

Linearisation:

RelationshipLinearised formPlotGradientIntercept
y=abxy = ab^xy=abxlog⁡y=xlog⁡b+log⁡a\log y = x\log b + \log alogy=xlogb+logalog⁡y\log ylogy vs xxxlog⁡b\log blogblog⁡a\log aloga
y=axny = ax^ny=axnlog⁡y=nlog⁡x+log⁡a\log y = n\log x + \log alogy=nlogx+logalog⁡y\log ylogy vs log⁡x\log xlogxnnnlog⁡a\log aloga

E. Sequences and Series

Sigma notation: ∑r=1nUr\displaystyle\sum_{r=1}^{n} U_rr=1∑n​Ur​ means the sum of UrU_rUr​ from r=1r = 1r=1 to r=nr = nr=n.

Arithmetic sequences (aaa = first term, ddd = common difference, lll = last term, nnn terms):

Tn=a+(n−1)dSn=n2[2a+(n−1)d]=n2(a+l)T_n = a + (n-1)d \qquad S_n = \frac{n}{2}[2a + (n-1)d] = \frac{n}{2}(a + l)Tn​=a+(n−1)dSn​=2n​[2a+(n−1)d]=2n​(a+l)

Geometric sequences (aaa = first term, rrr = common ratio):

Tn=arn−1r=Tn+1TnSn=a(1−rn)1−rT_n = ar^{n-1} \qquad r = \frac{T_{n+1}}{T_n} \qquad S_n = \frac{a(1 - r^n)}{1 - r}Tn​=arn−1r=Tn​Tn+1​​Sn​=1−ra(1−rn)​

Sum to infinity (converges when ∣r∣<1\lvert r \rvert < 1∣r∣<1 only):

S∞=a1−rS_\infty = \frac{a}{1 - r}S∞​=1−ra​

Section 2: Coordinate Geometry, Vectors, and Trigonometry

A. Coordinate Geometry

For two points (x1,y1)(x_1, y_1)(x1​,y1​) and (x2,y2)(x_2, y_2)(x2​,y2​):

m=y2−y1x2−x1d=(x2−x1)2+(y2−y1)2M=(x1+x22,  y1+y22)m = \frac{y_2 - y_1}{x_2 - x_1} \qquad d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \qquad M = \left(\frac{x_1 + x_2}{2},\; \frac{y_1 + y_2}{2}\right)m=x2​−x1​y2​−y1​​d=(x2​−x1​)2+(y2​−y1​)2​M=(2x1​+x2​​,2y1​+y2​​)

Parallel lines: equal gradients. Perpendicular lines: m1m2=−1m_1 m_2 = -1m1​m2​=−1.

Equation of a line: y−y1=m(x−x1)y - y_1 = m(x - x_1)y−y1​=m(x−x1​)

Circle equations:

FormEquationCentreRadius
Standard(x−a)2+(y−b)2=r2(x - a)^2 + (y - b)^2 = r^2(x−a)2+(y−b)2=r2(a,b)(a, b)(a,b)rrr
Generalx2+y2+2fx+2gy+c=0x^2 + y^2 + 2fx + 2gy + c = 0x2+y2+2fx+2gy+c=0(−f,−g)(-f, -g)(−f,−g)f2+g2−c\sqrt{f^2 + g^2 - c}f2+g2−c​

The tangent at a point on a circle is perpendicular to the radius at that point.

B. Vectors

For v=(xy)\mathbf{v} = \begin{pmatrix} x \\ y \end{pmatrix}v=(xy​):

∣v∣=x2+y2v^=v∣v∣\lvert\mathbf{v}\rvert = \sqrt{x^2 + y^2} \qquad \hat{\mathbf{v}} = \frac{\mathbf{v}}{\lvert\mathbf{v}\rvert}∣v∣=x2+y2​v^=∣v∣v​

Dot product:

(ab)⋅(cd)=ac+bd\begin{pmatrix} a \\ b \end{pmatrix} \cdot \begin{pmatrix} c \\ d \end{pmatrix} = ac + bd(ab​)⋅(cd​)=ac+bd

Angle between vectors:

cos⁡θ=a⋅b∣a∣∣b∣\cos\theta = \frac{\mathbf{a} \cdot \mathbf{b}}{\lvert\mathbf{a}\rvert\lvert\mathbf{b}\rvert}cosθ=∣a∣∣b∣a⋅b​

  • a⋅b=0\mathbf{a} \cdot \mathbf{b} = 0a⋅b=0: vectors are perpendicular.
  • b=ka\mathbf{b} = k\mathbf{a}b=ka for some scalar kkk: vectors are parallel.
  • Three points AAA, BBB, CCC are collinear if AB→=kAC→\overrightarrow{AB} = k\overrightarrow{AC}AB=kAC.

Direction of a vector: θ=arctan⁡ ⁣(yx)\theta = \arctan\!\left(\dfrac{y}{x}\right)θ=arctan(xy​), then adjust for the correct quadrant (add 180∘180^\circ180∘ in Q2 or Q3).

C. Trigonometry

Conversion:

θ∘×π180→radθ  rad×180π→∘\theta^\circ \times \frac{\pi}{180} \to \text{rad} \qquad \theta\;\text{rad} \times \frac{180}{\pi} \to {}^\circθ∘×180π​→radθrad×π180​→∘

Arc and sector (θ\thetaθ in radians):

l=rθAsector=12r2θAsegment=12r2(θ−sin⁡θ)l = r\theta \qquad A_{\text{sector}} = \frac{1}{2}r^2\theta \qquad A_{\text{segment}} = \frac{1}{2}r^2(\theta - \sin\theta)l=rθAsector​=21​r2θAsegment​=21​r2(θ−sinθ)

Exact values:

θ\thetaθ00030∘30^\circ30∘45∘45^\circ45∘60∘60^\circ60∘90∘90^\circ90∘
sin⁡θ\sin\thetasinθ00012\dfrac{1}{2}21​22\dfrac{\sqrt{2}}{2}22​​32\dfrac{\sqrt{3}}{2}23​​111
cos⁡θ\cos\thetacosθ11132\dfrac{\sqrt{3}}{2}23​​22\dfrac{\sqrt{2}}{2}22​​12\dfrac{1}{2}21​000
tan⁡θ\tan\thetatanθ00013\dfrac{1}{\sqrt{3}}3​1​1113\sqrt{3}3​undef.

CAST rule: All (Q1), Sine (Q2), Tangent (Q3), Cosine (Q4) are positive.

Graph properties:

FunctionPeriodAmplitude
y=asin⁡(kx)y = a\sin(kx)y=asin(kx)2πk\dfrac{2\pi}{k}k2π​∣a∣\lvert a \rvert∣a∣
y=acos⁡(kx)y = a\cos(kx)y=acos(kx)2πk\dfrac{2\pi}{k}k2π​∣a∣\lvert a \rvert∣a∣
y=atan⁡(kx)y = a\tan(kx)y=atan(kx)πk\dfrac{\pi}{k}kπ​—

Pythagorean identities:

sin⁡2θ+cos⁡2θ=1tan⁡2θ+1=sec⁡2θ\sin^2\theta + \cos^2\theta = 1 \qquad \tan^2\theta + 1 = \sec^2\thetasin2θ+cos2θ=1tan2θ+1=sec2θ

Compound angle formulas:

sin⁡(A±B)=sin⁡Acos⁡B±cos⁡Asin⁡B\sin(A \pm B) = \sin A\cos B \pm \cos A\sin Bsin(A±B)=sinAcosB±cosAsinB

cos⁡(A±B)=cos⁡Acos⁡B∓sin⁡Asin⁡B\cos(A \pm B) = \cos A\cos B \mp \sin A\sin Bcos(A±B)=cosAcosB∓sinAsinB

tan⁡(A±B)=tan⁡A±tan⁡B1∓tan⁡Atan⁡B\tan(A \pm B) = \frac{\tan A \pm \tan B}{1 \mp \tan A\tan B}tan(A±B)=1∓tanAtanBtanA±tanB​

Double angle formulas:

sin⁡2A=2sin⁡Acos⁡A\sin 2A = 2\sin A\cos Asin2A=2sinAcosA

cos⁡2A=cos⁡2A−sin⁡2A=1−2sin⁡2A=2cos⁡2A−1\cos 2A = \cos^2 A - \sin^2 A = 1 - 2\sin^2 A = 2\cos^2 A - 1cos2A=cos2A−sin2A=1−2sin2A=2cos2A−1

tan⁡2A=2tan⁡A1−tan⁡2A\tan 2A = \frac{2\tan A}{1 - \tan^2 A}tan2A=1−tan2A2tanA​

Section 3: Introductory Calculus

A. Differentiation

f(x)f(x)f(x)f′(x)f'(x)f′(x)
xnx^nxnnxn−1nx^{n-1}nxn−1
sin⁡(ax)\sin(ax)sin(ax)acos⁡(ax)a\cos(ax)acos(ax)
cos⁡(ax)\cos(ax)cos(ax)−asin⁡(ax)-a\sin(ax)−asin(ax)

Chain rule (let u=g(x)u = g(x)u=g(x), y=f(u)y = f(u)y=f(u)):

dydx=dydu⋅dudx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}dxdy​=dudy​⋅dxdu​

Product rule (y=uvy = uvy=uv):

dydx=udvdx+vdudx\frac{dy}{dx} = u\frac{dv}{dx} + v\frac{du}{dx}dxdy​=udxdv​+vdxdu​

Quotient rule (y=uvy = \dfrac{u}{v}y=vu​):

dydx=vdudx−udvdxv2\frac{dy}{dx} = \frac{v\dfrac{du}{dx} - u\dfrac{dv}{dx}}{v^2}dxdy​=v2vdxdu​−udxdv​​

Stationary points: set f′(x)=0f'(x) = 0f′(x)=0, solve for xxx, find yyy.

Second derivative at stationary pointNature
f′′(x)>0f''(x) > 0f′′(x)>0Minimum
f′′(x)<0f''(x) < 0f′′(x)<0Maximum
f′′(x)=0f''(x) = 0f′′(x)=0Inconclusive; use sign-change test on f′(x)f'(x)f′(x)

Tangent and normal at (x0,y0)(x_0, y_0)(x0​,y0​): tangent gradient mT=f′(x0)m_T = f'(x_0)mT​=f′(x0​); normal gradient mN=−1mTm_N = -\dfrac{1}{m_T}mN​=−mT​1​.

Connected rates: dydt=dydx⋅dxdt\dfrac{dy}{dt} = \dfrac{dy}{dx} \cdot \dfrac{dx}{dt}dtdy​=dxdy​⋅dtdx​

B. Integration

∫xn dx=xn+1n+1+c(n≠−1)\int x^n\,dx = \frac{x^{n+1}}{n+1} + c \qquad (n \neq -1)∫xndx=n+1xn+1​+c(n=−1)

∫(ax+b)n dx=(ax+b)n+1a(n+1)+c\int (ax + b)^n\,dx = \frac{(ax + b)^{n+1}}{a(n+1)} + c∫(ax+b)ndx=a(n+1)(ax+b)n+1​+c

∫sin⁡(ax) dx=−1acos⁡(ax)+c∫cos⁡(ax) dx=1asin⁡(ax)+c\int \sin(ax)\,dx = -\frac{1}{a}\cos(ax) + c \qquad \int \cos(ax)\,dx = \frac{1}{a}\sin(ax) + c∫sin(ax)dx=−a1​cos(ax)+c∫cos(ax)dx=a1​sin(ax)+c

Area under a curve between x=ax = ax=a and x=bx = bx=b:

A=∫aby dxA = \int_a^b y\,dxA=∫ab​ydx

Area between two curves (f(x)≥g(x)f(x) \geq g(x)f(x)≥g(x) on [a,b][a,b][a,b]):

A=∫ab[f(x)−g(x)] dxA = \int_a^b \bigl[f(x) - g(x)\bigr]\,dxA=∫ab​[f(x)−g(x)]dx

Volume of revolution about the xxx-axis:

V=π∫aby2 dxV = \pi\int_a^b y^2\,dxV=π∫ab​y2dx

Kinematics

Displacement sss, velocity vvv, acceleration aaa, time ttt:

v=dsdta=dvdt=d2sdt2v = \frac{ds}{dt} \qquad a = \frac{dv}{dt} = \frac{d^2s}{dt^2}v=dtds​a=dtdv​=dt2d2s​

s=∫v dtv=∫a dts = \int v\,dt \qquad v = \int a\,dts=∫vdtv=∫adt

SUVAT equations (uniform acceleration only; uuu = initial velocity, sss = displacement):

v=u+ats=ut+12at2v2=u2+2ass=12(u+v)tv = u + at \qquad s = ut + \tfrac{1}{2}at^2 \qquad v^2 = u^2 + 2as \qquad s = \tfrac{1}{2}(u + v)tv=u+ats=ut+21​at2v2=u2+2ass=21​(u+v)t

Particle is stationary when v=0v = 0v=0. Direction changes when vvv changes sign.

Section 4: Probability and Statistics

A. Data Representation and Analysis

Mean:

xˉ=∑xn(ungrouped)xˉ=∑fx∑f(grouped)\bar{x} = \frac{\sum x}{n} \quad \text{(ungrouped)} \qquad \bar{x} = \frac{\sum fx}{\sum f} \quad \text{(grouped)}xˉ=n∑x​(ungrouped)xˉ=∑f∑fx​(grouped)

Variance and standard deviation:

S2=∑(x−xˉ)2nS=∑(x−xˉ)2n(ungrouped)S^2 = \frac{\sum(x - \bar{x})^2}{n} \qquad S = \sqrt{\frac{\sum(x - \bar{x})^2}{n}} \quad \text{(ungrouped)}S2=n∑(x−xˉ)2​S=n∑(x−xˉ)2​​(ungrouped)

S2=∑f(x−xˉ)2∑f(grouped)S^2 = \frac{\sum f(x - \bar{x})^2}{\sum f} \quad \text{(grouped)}S2=∑f∑f(x−xˉ)2​(grouped)

Measures of spread:

Range=xmax⁡−xmin⁡IQR=Q3−Q1Semi-IQR=Q3−Q12\text{Range} = x_{\max} - x_{\min} \qquad \text{IQR} = Q_3 - Q_1 \qquad \text{Semi-IQR} = \frac{Q_3 - Q_1}{2}Range=xmax​−xmin​IQR=Q3​−Q1​Semi-IQR=2Q3​−Q1​​

Skewness:

Box plot patternSkewOrder of averages
Right whisker longer / Q3−Q2>Q2−Q1Q_3 - Q_2 > Q_2 - Q_1Q3​−Q2​>Q2​−Q1​PositiveMode < Median < Mean
Left whisker longer / Q3−Q2<Q2−Q1Q_3 - Q_2 < Q_2 - Q_1Q3​−Q2​<Q2​−Q1​NegativeMean < Median < Mode
SymmetricNoneMode = Median = Mean

B. Probability Theory

P(A)=favourable outcomestotal outcomesP(A′)=1−P(A)0≤P(A)≤1P(A) = \frac{\text{favourable outcomes}}{\text{total outcomes}} \qquad P(A') = 1 - P(A) \qquad 0 \leq P(A) \leq 1P(A)=total outcomesfavourable outcomes​P(A′)=1−P(A)0≤P(A)≤1

RuleFormula
Addition (general)P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B)P(A∪B)=P(A)+P(B)−P(A∩B)
Mutually exclusive (A∩B=∅A \cap B = \emptysetA∩B=∅)P(A∪B)=P(A)+P(B)P(A \cup B) = P(A) + P(B)P(A∪B)=P(A)+P(B)
ConditionalP(A∣B)=P(A∩B)P(B)P(A \mid B) = \dfrac{P(A \cap B)}{P(B)}P(A∣B)=P(B)P(A∩B)​
IndependentP(A∩B)=P(A)⋅P(B)P(A \cap B) = P(A) \cdot P(B)P(A∩B)=P(A)⋅P(B)

Two non-zero-probability events cannot be simultaneously mutually exclusive and independent.

Tree diagrams: multiply along branches for intersection probabilities; add across branches for union. The syllabus restricts trees to two initial branches.

Venn diagrams: restricted to two sets; the four regions (AAA only, BBB only, A∩BA \cap BA∩B, neither) must sum to P(S)=1P(S) = 1P(S)=1.

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