Vector notation, addition, subtraction and scalar multiplication, magnitude, unit vectors, displacement vectors, the scalar product, angle between vectors, and parallel and perpendicular vectors.
A vector has both magnitude and direction. A scalar has magnitude only. Velocity, displacement, and force are vectors; speed, mass, and temperature are scalars.
Notation
Vectors are written in bold (a) in typeset text, or underlined (a) in handwriting. In two dimensions, a vector is expressed as a column vector
v=(xy)
or in terms of the standard unit vectors i=(10) and j=(01) as v=xi+yj.
A position vectorOP describes the location of point P relative to the origin O.
Operations on Vectors
Addition and subtraction: add or subtract corresponding components.
(ab)+(cd)=(a+cb+d)
Scalar multiplication: multiply each component by the scalar k. This scales the magnitude by ∣k∣ and reverses direction if k<0.
k(ab)=(kakb)
Equal vectors have the same magnitude and direction; position does not matter.
Magnitude
The magnitude (length) of v=(xy) is:
∣v∣=x2+y2
This is Pythagoras applied to the horizontal and vertical components.
Example
(5−12)=25+144=169=13
Direction of a Vector
The direction of a vector is the angle it makes with the positive x-axis, measured anticlockwise. For a vector with components (x,y):
θ=arctan(xy)
arctan returns values between −90∘ and 90∘, so the quadrant must be checked. For a vector in Quadrant II or III, add 180∘ to the result.
Example
Find the direction of v=−3i+3j.
arctan(−33)=arctan(−1)=−45∘.
Since x<0 and y>0 the vector is in Quadrant II, so direction =−45∘+180∘=135∘.
Unit Vectors
A unit vector has magnitude 1. To find the unit vector in the direction of a:
a^=∣a∣a
Example
Find the unit vector in the direction of a=(34).
∣a∣=9+16=5
a^=51(34)=(3/54/5)
Displacement Vectors
The vector from point A to point B is:
AB=OB−OA=b−a
Equivalently, AB=B−A (coordinates of B minus coordinates of A). The order matters: AB=−BA.
Example
If A=(2,−1) and B=(7,4):
AB=(7−24−(−1))=(55)
Parallel and Collinear Vectors
Two vectors are parallel if one is a scalar multiple of the other: b=ka for some scalar k.
Three points A, B, C are collinear if AB is parallel to AC (and both share point A).
Example
Show that A=(1,2), B=(3,6), C=(5,10) are collinear.
AB=(24) and AC=(48)=2(24)
Since AC=2AB and they share point A, the three points are collinear.
The Scalar (Dot) Product
The scalar product of a=(a1a2) and b=(b1b2) is defined two ways:
Component form:
a⋅b=a1b1+a2b2
Geometric form:
a⋅b=∣a∣∣b∣cosθ
where θ is the angle between the vectors (0≤θ≤π).
The result is a scalar (a number), not a vector.
Finding the Angle Between Two Vectors
Combining both definitions:
cosθ=∣a∣∣b∣a⋅b
Example
Find the angle between a=(12) and b=(3−1).
a⋅b=(1)(3)+(2)(−1)=1
∣a∣=5, ∣b∣=10
cosθ=5⋅101=501=521⇒θ=arccos(521)≈81.9°
Perpendicular Vectors
Two non-zero vectors are perpendicular if and only if their dot product is zero:
a⋅b=0⟺a⊥b
This follows directly from the geometric form: cos90°=0.
Example
Are p=(4−3) and q=(34) perpendicular?
p⋅q=(4)(3)+(−3)(4)=12−12=0. Yes, they are perpendicular.
Exam Tip
Paper 02 often asks you to find an unknown component given that two vectors are perpendicular. Set the dot product equal to zero and solve for the unknown.
Properties of the Scalar Product
Commutative: a⋅b=b⋅a
a⋅a=∣a∣2 (useful for finding ∣a∣ without the square root formula when the vector is expressed algebraically)
Distributive: a⋅(b+c)=a⋅b+a⋅c (used when expanding expressions involving sums of vectors)