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Mathematics

Algebraic Expressions

PDF
Matthew Williams
|May 6, 2026|7 min read
AlgebraExpressionsPaper 01Paper 02Substitution

Symbolic representation, operations on expressions, substitution, and binary operations.

Algebra is a language for describing patterns before you know the exact numbers. A letter such as xxx or nnn lets you write one rule that works for many possible values.

CSEC tests algebra at all three cognitive levels: knowing symbols, simplifying expressions correctly, and modelling word problems. Each example shows what a symbol represents and why each operation is used.

Symbolic Representation

Symbols let you describe a general situation. Before simplifying or solving, decide what each letter stands for; otherwise the expression becomes a string of signs instead of a statement with meaning.

In algebra, we use letters to represent numbers:

  • xxx, yyy, aaa, bbb = variables (unknown quantities)
  • 3x3x3x = 3 times some number
  • x+5x + 5x+5 = some number plus 5
  • 2a−b2a - b2a−b = twice aaa, minus bbb

Translating Between Words and Algebra

Word problems become easier when you translate one phrase at a time. Look for operation words: "sum" suggests addition, "difference" suggests subtraction, "product" suggests multiplication, and "quotient" suggests division.

Example/Words and algebra

1. Word phrase → algebraic expression

  • "A number increased by 7" → x+7x + 7x+7
  • "Twice a number minus 3" → 2x−32x - 32x−3
  • "The sum of two consecutive numbers" → x+(x+1)=2x+1x + (x + 1) = 2x + 1x+(x+1)=2x+1
  • "The product of a number and 5" → 5x5x5x
  • "A number divided by 2" → x2\frac{x}{2}2x​

2. Algebraic expression → word phrase

  • 3a+23a + 23a+2 → "Three times aaa, plus 2"
  • y4\frac{y}{4}4y​ → "A quarter of yyy"
  • 5−x5 - x5−x → "5 minus a number"

Directed Numbers (Signed Numbers)

Directed numbers show direction from zero. A negative sign may mean debt, below sea level, loss, reverse movement, or temperature below zero, depending on the context.

Positive numbers are greater than zero. Negative numbers are less than zero.

(−3)+(+5)=2(-3) + (+5) = 2(−3)+(+5)=2 (−3)+(−5)=−8(-3) + (-5) = -8(−3)+(−5)=−8 (−3)×(−5)=15(-3) \times (-5) = 15(−3)×(−5)=15

Rules:

  • Same signs multiply to positive: (+)×(+)=(+)(+) \times (+) = (+)(+)×(+)=(+) and (−)×(−)=(+)(-) \times (-) = (+)(−)×(−)=(+)
  • Different signs multiply to negative: (+)×(−)=(−)(+) \times (-) = (-)(+)×(−)=(−)
Example

(−4)×(−7)=28(-4) \times (-7) = 28(−4)×(−7)=28 (both negative → positive)

(−4)×7=−28(-4) \times 7 = -28(−4)×7=−28 (different signs → negative)

(−3)−(−8)=−3+8=5(-3) - (-8) = -3 + 8 = 5(−3)−(−8)=−3+8=5 (subtract negative = add)

Operations with Algebraic Expressions

Adding and Subtracting Like Terms

Like terms can be combined because they count the same kind of object. Three xxx's plus five xxx's make eight xxx's, but three xxx's plus five yyy's must stay separate.

Like terms have the same variable and power.

3x+5x=8x3x + 5x = 8x3x+5x=8x 2a2+3a2=5a22a^2 + 3a^2 = 5a^22a2+3a2=5a2 3x+5y cannot be combined (different variables)3x + 5y \text{ cannot be combined (different variables)}3x+5y cannot be combined (different variables)

Example

Simplify: 4x+3y−2x+5y4x + 3y - 2x + 5y4x+3y−2x+5y

Group like terms: (4x−2x)+(3y+5y)=2x+8y(4x - 2x) + (3y + 5y) = 2x + 8y(4x−2x)+(3y+5y)=2x+8y

Multiplication and Division of Expressions

Multiplication spreads a factor across every term in a bracket. Division does the reverse by sharing each term by the same divisor.

Multiply: Use the distributive law a(b+c)=ab+aca(b + c) = ab + aca(b+c)=ab+ac

2×(x+3)=2x+62 \times (x + 3) = 2x + 62×(x+3)=2x+6 x×(x+5)=x2+5xx \times (x + 5) = x^2 + 5xx×(x+5)=x2+5x

Divide: Divide each term by the divisor

6x+93=6x3+93=2x+3\frac{6x + 9}{3} = \frac{6x}{3} + \frac{9}{3} = 2x + 336x+9​=36x​+39​=2x+3

Expanding Brackets

Expanding removes brackets by multiplying. It is useful when an expression must be simplified or compared with another expression in standard form.

Distributive law: a(b+c)=ab+aca(b + c) = ab + aca(b+c)=ab+ac

Example

Single bracket:

3(2x+5)=6x+153(2x + 5) = 6x + 153(2x+5)=6x+15

x(x−4)=x2−4xx(x - 4) = x^2 - 4xx(x−4)=x2−4x

Distributive Law

Double brackets: (a+b)(c+d)=ac+ad+bc+bd(a + b)(c + d) = ac + ad + bc + bd(a+b)(c+d)=ac+ad+bc+bd

Example

(x+3)(x+5)(x + 3)(x + 5)(x+3)(x+5)

Using FOIL (First, Outer, Inner, Last):

  • First: x×x=x2x \times x = x^2x×x=x2
  • Outer: x×5=5xx \times 5 = 5xx×5=5x
  • Inner: 3×x=3x3 \times x = 3x3×x=3x
  • Last: 3×5=153 \times 5 = 153×5=15

x2+5x+3x+15=x2+8x+15x^2 + 5x + 3x + 15 = x^2 + 8x + 15x2+5x+3x+15=x2+8x+15

FOIL Method
Example

(2x−3)(x+4)(2x - 3)(x + 4)(2x−3)(x+4)

=2x(x)+2x(4)+(−3)(x)+(−3)(4)= 2x(x) + 2x(4) + (-3)(x) + (-3)(4)=2x(x)+2x(4)+(−3)(x)+(−3)(4) =2x2+8x−3x−12= 2x^2 + 8x - 3x - 12=2x2+8x−3x−12 =2x2+5x−12= 2x^2 + 5x - 12=2x2+5x−12

Substitution and Binary Operations

Substitution

Substitution turns a general expression into a specific value. Brackets are important because they preserve signs, especially when substituting negative numbers.

Substitution means: replace the letter with the number you're given, then calculate.

Why this matters: Many algebra problems ask "What happens if x equals this number?" Substitution lets you find the answer by plugging in the value.

The Three-Step Process

Step 1: Identify which variable is being replaced and what value it gets

Step 2: Replace every instance of that letter with the value (use brackets to avoid confusion)

Step 3: Follow the order of operations (PEMDAS: Powers, Multiplication/Division, Addition/Subtraction)

Example/Example 1: Simple Expression

If x=3x = 3x=3, find 2x2+5x−12x^2 + 5x - 12x2+5x−1:

Step 1: We're replacing xxx with 3

Step 2: Write with brackets: 2(3)2+5(3)−12(3)^2 + 5(3) - 12(3)2+5(3)−1

Step 3: Calculate carefully in order:

  • Powers first: (3)2=9(3)^2 = 9(3)2=9
  • Then: 2(9)+5(3)−1=18+15−12(9) + 5(3) - 1 = 18 + 15 - 12(9)+5(3)−1=18+15−1
  • Finally: 18+15−1=3218 + 15 - 1 = 3218+15−1=32

Answer: 32

Example/Example 2: Multiple Variables

If a=2,b=3a = 2, b = 3a=2,b=3, find 3a2+2ab−b3a^2 + 2ab - b3a2+2ab−b:

Step 1: Replace aaa with 2 and bbb with 3

Step 2: Write with brackets: 3(2)2+2(2)(3)−(3)3(2)^2 + 2(2)(3) - (3)3(2)2+2(2)(3)−(3)

Step 3: Calculate in order:

  • Powers: (2)2=4(2)^2 = 4(2)2=4
  • Multiplication: 3(4)=123(4) = 123(4)=12, 2(2)(3)=122(2)(3) = 122(2)(3)=12
  • Addition and subtraction: 12+12−3=2112 + 12 - 3 = 2112+12−3=21

Answer: 21

Key tip: When you have multiple variables, be EXTRA careful to replace each one correctly.

When Substitution Goes Wrong

Remember

Common mistakes:

  • Forgetting PEMDAS order (doing addition before powers)
  • Not replacing ALL instances of the variable
  • Arithmetic errors in the calculation step

Check yourself: Substitute your answer back and make sure the math works!

Binary Operations

For binary operations, the symbol is only a label for a rule. Do not assume it behaves like ordinary multiplication or addition unless the definition says so.

A binary operation is a special rule that tells you how to combine two numbers. It's not just the normal operations (+, −, ×, ÷), it can be anything!

Why learn this? Tests use binary operations to check if you can follow instructions and substitute correctly. It's a skill test, not a math test.

Reading a Binary Operation Definition

When you see "a∗b=2a+ba * b = 2a + ba∗b=2a+b", it means:

  • ∗*∗ is the special symbol (could be anything: ★, ⊕, ◆, etc.)
  • aaa is the FIRST number
  • bbb is the SECOND number
  • The rule is: multiply the first number by 2, then add the second number
Example

The operation a∗b=2a+ba * b = 2a + ba∗b=2a+b. Find 3∗53 * 53∗5:

Step 1: Identify: a=3a = 3a=3, b=5b = 5b=5

Step 2: Use the rule 2a+b2a + b2a+b: 3∗5=2(3)+5=6+5=113 * 5 = 2(3) + 5 = 6 + 5 = 113∗5=2(3)+5=6+5=11

Answer: 11

Nested Operations (Operations Inside Operations)

When you see 2∗(3∗1)2 * (3 * 1)2∗(3∗1), solve the parentheses FIRST.

Example

Find 2∗(3∗1)2 * (3 * 1)2∗(3∗1) where a∗b=2a+ba * b = 2a + ba∗b=2a+b:

Step 1: Do the inner operation first: 3∗13 * 13∗1 3∗1=2(3)+1=6+1=73 * 1 = 2(3) + 1 = 6 + 1 = 73∗1=2(3)+1=6+1=7

Step 2: Now use that result: 2∗72 * 72∗7 2∗7=2(2)+7=4+7=112 * 7 = 2(2) + 7 = 4 + 7 = 112∗7=2(2)+7=4+7=11

Answer: 11

Important: Order matters! (a∗b)∗c(a * b) * c(a∗b)∗c is NOT the same as a∗(b∗c)a * (b * c)a∗(b∗c) (these operations aren't "associative")

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